25x=5x^2-3

Solution for 25x=5x^2-3 equation:

25x=5x^2-3

We move all terms to the left:

25x-(5x^2-3)=0

We get rid of parentheses

-5x^2+25x+3=0

a = -5; b = 25; c = +3;
Δ = b2-4ac
Δ = 252-4·(-5)·3
Δ = 685
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{685}}{2*-5}=\frac{-25-\sqrt{685}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{685}}{2*-5}=\frac{-25+\sqrt{685}}{-10}
$